Y=-16t^2+96t+5

Solution for Y=-16t^2+96t+5 equation:

=-16Y^2+96Y+5

We move all terms to the left:

-(-16Y^2+96Y+5)=0

We get rid of parentheses

16Y^2-96Y-5=0

a = 16; b = -96; c = -5;
Δ = b2-4ac
Δ = -962-4·16·(-5)
Δ = 9536
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9536}=\sqrt{64*149}=\sqrt{64}*\sqrt{149}=8\sqrt{149}$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-8\sqrt{149}}{2*16}=\frac{96-8\sqrt{149}}{32}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+8\sqrt{149}}{2*16}=\frac{96+8\sqrt{149}}{32}
$